The equation of the plane is x - 2y + 2z = 2. It's also given that the plane meets the x-axis at P, the y-axis at Q and the z-axis at R.
How do I find those 3 (P, Q, R) vectors?|||//
x=2
y=-1
z=1
so those vectors are %26lt;2,0,0%26gt;%26lt;0,-1,0%26gt;%26lt;0,0,1%26gt;|||The points at which the plane meets the three axes are:
x = 2/1 = 2
y = -2/2 = -1
z = 2/2 = 1
P = %26lt;2, 0, 0%26gt;
Q = %26lt;0, -1, 0%26gt;
R = %26lt;0, 0, 1%26gt;
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