How would i graph a system of inequalities on a coordinate plane?

The system of inequalities, that i have to graph on a coordinate plane, has 5 inequalities: x%26gt;=9, x%26lt;=36, y%26gt;=55, y%26lt;=110 and x+y%26gt;=80.


I think that you have to put it in slope-intercept form...





%26lt;= means les than or equal to.|||If you need to graph these inequalities on the same coordinate plane, then this will be the area bounded by lines x = 9 (to the left), x = 36 (on the right), y = 55 (at bottom), y = 110 (at top), and above line y = -x + 80.





Check out link below:


http://i48.tinypic.com/29pyjur.jpg|||graph them like a regular line, but shade in the areas that correspond to the equation. If it is just greater than use a dotted line, but these are all greater than or equal to, so use a solid line.





For the first one: draw a solid vertical line at X=9, then shade in the area to the right because it is saying x is greater.





hope that helps|||put it in slope intercept form, and draw normally.





if the sign is %26gt; or %26lt; than the line you draw will be a DOTTED line such as:





- - - - - - -





if the sign is %26gt;= or %26lt;= it will be SOLID like a normal graph





now, if the sign is %26lt; or %26lt;= you shade in the region to the left of the graph





if the sign is %26gt; or %26gt;= you shade in the region to the right of the graph