A jet plane took off for a 7,956-km journey against the 120-kph wind to another airport. It took the plane 2 hours and 24 minutes less time in returning than in going.|||No. of hours going (t) in terms of speed (x):
t = 7,956/(x - 120)
t = 7,956/(x + 120) + 2.4
t = (7,956 + 2.4x + 288)/(x + 120)
t = (8,244 + 2.4x)/(x + 120)
Speed鈥攛:
(x - 120)(8,244 + 2.4x) = 7,956(x + 120)
8,244x + 2.4x虏 - 989,280 - 288x = 7,956x + 954,720
2.4x虏 = 1,944,000
x虏 = 810,000
x = 900
Answer: 900 kph is the speed of the plane.|||t1 = 7956/(v + 120)
t2 = 7956/(v - 120)
t2 - t1 = 2 hours and 24 minutes = 2.4 hrs
7956/(v - 120) - 7956/(v + 120) = 2.4
v = 900 kph
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment